\(5x+x=30\)
\(x\left(5+1\right)=30\)
\(6x=30\)
\(\Leftrightarrow x=5\)
\(8x+2x=100\)
\(x\left(8+2\right)=100\)
\(10x=100\)
\(x=10\)
a) 5x + x = 30
\(\Leftrightarrow\)6x = 30
\(\Rightarrow\)x = 5
Vậy x = 5
b) 8x + 2x = 100
\(\Leftrightarrow\)10x = 100
\(\Rightarrow\)x = 10
Vậy x = 10
5x + x = 30
=> x . ( 5 + 1 ) = 30
=> x . 6 = 30
=> x = 30 : 6
=> x = 5
Vậy x = 5
8x + 2x = 100
=> x . ( 8 + 2 ) = 100
=> x . 10 = 100
=> x = 100 : 10
=> x = 10
Vậy x = 10
5x + x = 30
6x = 30
x = 30 : 6
x = 5
8x + 2x = 100
10x = 100
x = 100 : 10
x = 10
a) 5x+x=30 (ĐKXĐ:x \(\varepsilon\)R)
<=>x(5+1)=30
<=>6x=30
<=>x=\(\frac{30}{6}\)=5 (thỏa mãn điều kiện xác định)
Vậy x=5
b) 8x+2x=100 (ĐKXĐ:x\(\varepsilonℝ\))
<=>x(8+2)=100
<=>10x=100
<=>x=10 ( thỏa mãn điều kiện xác định)
Vậy x=10
5x + x = 30
x = 5
8x + 2x = 100
x = 10
TL :
\(5x+x=30\)
\(x\left(5+1\right)=30\)
\(6x=30\)
\(x=30:6\)
\(x=5\)
\(8x+2x=100\)
\(x\left(8+2\right)=100\)
\(10x=100\)
\(x=100:10\)
\(x=10\)
5x+x=30
==>x^2=30-5
==>x^2=25
==>x^2=5^2
==>x=5
8x+2x=100
==>10x=100
==>x=100:10
==>x=10