Question

Tìm x

4x²-2x+3-4x(x-5)=7x-3

Answer 1

\(4x^2-2x+3-4x^2+20x-7x+3=0\)

\(11x+6=0\)

\(11x=-6\)

\(x=-\frac{6}{11}\)

Answer 2

\(4x^2-2x+3-4x\left(x-5\right)=7x-3\)

\(4x^2-2x+3-4x^2+20x=7x-3\)

\(11x=-6\)

\(x=-\frac{6}{11}\)

Answer 3

\(4x^2-2x+3-4x^2+20x-7x+3=0\)

\(=>11x+6=0\)

\(=>11x=-6\)

\(=>x=\frac{-6}{11}\)

Answer 4

Kq x=-6/11