=> 4x[1 + 43] = 4160
=> 4x . 65 = 4160
=> 4x = 64
=> x = 3
Ta có: 4\(^x\)+4\(^{x+3}\)=4160
\(\Rightarrow\)4\(^x\).(1+4\(^3\))=4160
\(\Rightarrow\)4\(^x\).65=4160
\(\Rightarrow\)4\(^x\)=64
\(\Rightarrow\)4\(^x\)=4\(^3\)\(\Rightarrow\)x=3
4\(^x\)+4\(^x\).64=4160
4\(^x\)(1+64)= 4160
4\(^x\)=4160:65=64
4\(^x\)=4\(^3\)
\(\Rightarrow\)x=3