\(\Leftrightarrow\left[{}\begin{matrix}\dfrac{4}{9}x+\dfrac{1}{2}=\dfrac{1}{5}\\\dfrac{4}{9}x+\dfrac{1}{2}=-\dfrac{1}{5}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{27}{40}\\x=-\dfrac{63}{40}\end{matrix}\right.\)
\(=>\dfrac{4}{9}x+\dfrac{1}{2}=\dfrac{1}{5}\)
\(\dfrac{4}{9}x=\dfrac{1}{5}-\dfrac{1}{2}\)
\(\dfrac{4}{9}x=\dfrac{-3}{10}\)
\(x=\dfrac{27}{40}\)
hay \(\dfrac{4}{9}x+\dfrac{1}{2}=\dfrac{-1}{5}=>\dfrac{-63}{40}\)