Question

tìm x

3x(x²+1) - 6 ( x²+1)=0

Answer 1

3x(x²+1) - 6 ( x²+1)=0

=> (x²+1) (3x - 6) = 0

=> x²+1 = 0 => x² = -1 => x = -\(\sqrt{1}^2\)

3x - 6 = 0 => 3x = 6 => x = 2

t i c k nhé!! 466457775757887687689768568989680780986734573465

Answer 2

\(3x\left(x^2+1\right)-6\left(x^2+1\right)=0\)

\(\Rightarrow\left(x^2+1\right)\left(3x-6\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x^2+1=0\\3x-6=0\end{cases}}\Rightarrow\orbr{\begin{cases}x^2=-1\left(ktm\right)\\x=2\end{cases}}\)

Vậy x = 2