Question

Tìm x

(3x+1) nhân \(\left(-\dfrac{1}{3}x-2\right)\)

Answer 1

\(\left(3x+1\right)\left(-\dfrac{1}{3}x-2\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}3x+1=0\\-\dfrac{1}{3}x-2=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{3}\\x=-6\end{matrix}\right.\)

Answer 2

`(3x+1).(-1/3x-2)=0`

`@TH1:3x+1=0`

       `=>3x=-1`

       `=>x=[-1]/3`

`@TH2: -1/3x-2=0`

        `=>-1/3x=2`

        `=>x=-6`

Vậy `x=[-1]/3` hoặc `x=-6`

Answer 3

kết quả bằng 0 nhé 

mn tìm x nhanh giúp mình với ạ

Answer 4

x=0