3*=9 <=> 3*=3^2 => x=2
( x-1 )^3=8 <=> (x-1)^3=2^3 <=> x-1=2 <=> x=3
\(3^x=9\)
\(3^x=3^2\)
Vậy \(x=2\)
\(\left(x-1\right)^3=8\)
\(\left(x-1\right)^3=2^3\)
\(\Rightarrow x-1=2\)
\(x=3\)
\(3^x=9\)
\(3^x=3^3\)
\(\Rightarrow x=3\)
\(\left(x-1\right)^3=8\)
\(\left(x-1\right)^3=2^3\)
\(\Rightarrow x-1=2\)
\(\Rightarrow x=2+1\)
\(\Rightarrow x=3\)
3x=9
=>3x=32
=>x=2
( x - 1 ) 3 = 8
=>(x-1)3=23
=>x-1=2
=>x=3
