\(\frac{3x-5}{2x+7}=\frac{4x+8}{5x-4}\)
\(\left(3x-5\right)\left(5x-4\right)=\left(4x+8\right)\left(2x+7\right)\)
\(15x^2-12x-10x+20=8x^2+28x+16x+56\)
\(15x^2-8x^2-12x-10x-28x-16x+20-56=0\)
\(7x^2-66x-36=0\)
bạn tự làm tiếp nha
(3x-5)/(2x+7)=(4x+8)/(5x-4)
<=>(3x-5)(5x-4)=(4x+8)(2x+7)
<=>15x-20=8x+56
<=>15x-8x=56+20
<=>7x=76
<=>x=76:7=76/7
\(\frac{3x-5}{2x+7}=\frac{4x+8}{5x-4}\)
\(\left(3x-5\right)\left(5x-4\right)=\left(4x+8\right)\left(2x+7\right)\)
\(3x.5x-4.3x-5.5x+5.4=4x.2x+7.4x+8.2x+8.7\)
\(15x^2-12x-10x+20=8x^2+28x+16x+56\)
\(15x^2-22x+20=8x^2+44x+56\)
\(15x^2-22x+20-8x^2-44x-56=0\)
\(7x^2-66x-36=0\)
Mấy bạn làm đúng rồi đó
k tui nha
thanks
