Áp dụng tính chất của dãy tỷ số bằng nhau
\(\frac{3x-1}{40-5x}=\frac{25-3x}{4x-34}=\frac{\left(3x-1\right)+\left(25x-3x\right)}{\left(40-5x\right)+\left(5x-34\right)}=4\)
\(\Rightarrow\frac{3x-1}{40-5x}=4\)
\(\Rightarrow3x-1=3\left(40-5x\right)\)
\(\Rightarrow3x-1=160-20x\)
\(\Rightarrow23x=161\)
\(\Rightarrow x=161:23\)
\(\Rightarrow x=7\)
3*x-1/40-5*x=25-3*x/5*x-34
tìm x,biết
a,∣∣∣X−25∣∣∣+12=34|X−25|+12=34
b,∣∣∣X−1710∣∣∣=2310|X−1710|=2310
c,∣∣∣x+35∣∣∣−12=12|x+35|−12=12
d,|2x−5|=3|2x−5|=3
e,2.|3x−1|+1=5|3x−1|+1=5
ai nhanh và đúng mk tick cho
tim x,y biet
a/ x/4 = y/5 va x+y = 4,08
b/ -34 = 7x va x-y =-40
c/ x/4 = 3/5 va x.y =1215
Tim x biet
1/1*3+1/3*5+1/5*7+1/7*9+...+1/x(x+2)=16/34
Tim x biet
1/1*3+1/3*5+1/5*7+1/7*9+...+1/x(x+2)=16/34
a, x+5/25+x-4/34+x+1/29=-3
a)tim GTNN cua
A=/x-2019/+(y-1)^2020-2
C=/x-3/+/x+4/-5
b)tim GTLN
B=3^2-4/x^2-25/
D=x-4/x-5
tìm x
a) ( 152\(\frac{2}{4}\)-148\(\frac{3}{8}\)) : 0,2 = X : 0,3
b) ( (6\(\frac{3}{5}\)-3\(\frac{3}{14}\)) -2,5 ) : ( 21-1,25) = X : 5\(\frac{5}{6}\)
c) (4-\(\frac{3}{4}\)) : ( 2\(\frac{1}{3}\)-1\(\frac{1}{9}\)) = 31. X : ( 45\(\frac{-10}{63}\)-44\(\frac{25}{84}\))
d) \(\frac{2.X+3}{5.X+2}\)=\(\frac{3.X-4}{7}\)
e) \(\frac{3.X-1}{40-5.X}\)=\(\frac{25-3.X}{5.X-34}\)
Tìm x biết:
a) (2x + 3)/(5x +2) = (4x + 5)/(10x + 2)
b) (3x - 1)/(40 - 5x) = (25 - 3x)/(5x - 34)
