Question

TÌM x:(3x-1)(2x+7)-(x+1)(6x-5)=16

 

Answer 1

(3x-1)(2x+7)-(x+1)(6x-5)=16

=6x^2+21x-2x-7-(6x^2-5x+6x-5)=16

=6x^2+21x-2x-7-6x^2+5x-6x+5=16

=18x-2=16

18x=16+2

18x=18

x=1

​vậy x=1

bn đùa mk à 

Answer 2

(3x-1)(2x+7)-(x+1)(6x-5)=16

=6x^2+21x-2x-7-(6x^2-5x+6x-5)=16

=6x^2+21x-2x-7-6x^2+5x-6x+5=16

=18x-2=16

18x=16+2

18x=18

x=1

​vậy x=1

Answer 3

(3x-1)(2x+7)-(x+1)(6x-5)=16
<=> (6x^2+21x-2x-7)-(6x^2-5x+6x-5)=16
<=> 6x^2+21x-2x-7-6x^2+5x-6x+5=16

<=> (6x^2 -6x^2) + ( 21x-2x+5x-6x)-(7+5)=166x)-(7+5)=16
<=>18x-2=16
<=>18x=18

<=> x=1

Answer 4

(3x - 1)(2x + 7) - (x + 1)(6x - 5) = 16

6x^2 + 21x - 2x - 7 - (6x^2 - 5x + 6x - 5) = 16

6x^2 + 21x - 2x - 7 - 6x^2 + 5x - 6x + 5 = 16

18x-2 = 16

18x = 16+2

18x = 18

x = 1

Answer 5

Coppy bài cũng hay lắm nhỉ thích làm CTV mak đi coppy trên H.vn 

Link đây nhé

https://h.vn/hoi-dap/question/60812.html

https://h7.net/hoi-dap/toan-8/tim-x-biet-3x-1-2x-7-x-1-6x-5-16-faq431092.html

Tìm x biết ( 3x-1 )( 2x+7 ) - ( x+1 )(6x-5)=16 - Thiên Mai - H7

https://h7.net/hoi-dap/toan.../tim-x-biet-3x-1-2x-7-x-1-6x-5-16-faq431092.html

 

6 thg 9, 2018 - a)(3x-1)(2x+7)-(x+1)(6x-5)=16. =6x^2+21x-2x-7-(6x^2-5x+6x-5)=16. =6x^2+21x-2x-7-6x^2+5x-6x+5=16. =18x-2=16. 18x=16+2. 18x=18. x=1.

Mọi người cũng tìm kiếm

(x^4+2x^3+10x-25):(x^2+5)=32x 5 )= 3 2

(2x+3)^2x-2(2x+3)(2x-5)+(2x-5)^2=x^2+6x+64

Answer 6

x=1 nha

Answer 7

\(\left(3x-1\right)\left(2x+7\right)-\left(x+1\right)\left(6x-5\right)=16\)

\(\Leftrightarrow\left(6x^2+19x-7\right)-\left(6x^2+x-5\right)=16\)

\(\Leftrightarrow6x^2+19x-7-6x^2-x+5=16\)

\(\Leftrightarrow18x-2=16\)

\(\Leftrightarrow18x=18\)

\(\Leftrightarrow x=1\)

Vậy nghiệm duy nhất của pt là 1

Answer 8

x=1

~hok tốt~