Question

tìm x

(2x-1)(3x+1)+(3x-4)(3-2x)=5

Answer 1

(2x-1)(3x+1)+(3x-4)(3-2x)=5

\(6x^2+2x-3x-1+9x-6x^2-12+8x=5\)

\(\left(6x^2-6x^2\right)+\left(2x-3x+9x+8x\right)+\left(-1-12\right)=5\)

\(16x-13=5\)

\(16x=5+13\)

\(16x=18\)

\(x=\frac{18}{16}\)

\(x=\frac{9}{8}\)

Answer 2

\(\left(2x-1\right)\left(3x+1\right)+\left(3x-4\right)\left(3-2x\right)=5\)

=>\(6x^2+2x-3x-1+9x-6x^2-12+8x=5\)

=>\(16x-13=5\)

=>\(16x=5+13=18\)

=>\(x=\frac{18}{16}=\frac{9}{8}\)