`1/3 + x/20 = 3/4`
`<=> x/20 = 3/4 - 1/3`
`<=> x/20 = 5/12`
Vậy `x = 5/12`
\(13+\dfrac{x}{20}=\dfrac{3}{4}\)
\(\dfrac{x}{20}=\dfrac{3}{4}-13\)
\(\dfrac{x}{20}=-\dfrac{49}{4}\)
\(x=\dfrac{\left(-49\cdot20\right)}{4}\)
\(x=-\dfrac{980}{4}\)
\(x=-245\)