Giải :
\(a,\dfrac{12+x}{42}=\dfrac{5}{6}\\ =>\dfrac{12+x}{42}=\dfrac{5\times7}{42}\\ =>12+x=35\\ =>x=35-12\\ =>x=23\)
Vậy \(x=23\)
\(b,\dfrac{25-x}{40}=\dfrac{3}{8}\\ =>\dfrac{25-x}{40}=\dfrac{3\times5}{40}\\ =>25-x=15\\ =>x=25-15\\ =>x=10\)
Vậy \(x=10\)
\(\dfrac{12+x}{42}=\dfrac{5}{6}\) hay \(12+\dfrac{x}{42}=\dfrac{5}{6}\) nhỉ bạn