Question

tìm x:

1) 7,5 - (\(\dfrac{1}{3}\)x + \(\dfrac{1}{6}\)) = \(\dfrac{1}{3}\)

2) 4,5 - (\(\dfrac{1}{2}\)x + \(\dfrac{1}{3}\)) = \(\dfrac{1}{6}\)

Answer 1

1)
     \(7,5-\left(\dfrac{1}{3}x+\dfrac{1}{6}\right)=\dfrac{1}{3}\)
\(\Leftrightarrow7,5-\dfrac{1}{3}x-\dfrac{1}{6}=\dfrac{1}{3}\)
\(\Leftrightarrow7,5-\dfrac{1}{3}x=\dfrac{1}{3}+\dfrac{1}{6}=\dfrac{1}{2}\)
\(\Leftrightarrow\dfrac{1}{3}x=7,5-\dfrac{1}{2}=7\)
\(\Leftrightarrow x=7:\dfrac{1}{3}=21\)
    Vậy \(x=21\)


2)
     \(4,5-\left(\dfrac{1}{2}x+\dfrac{1}{3}\right)=\dfrac{1}{6}\)
\(\Leftrightarrow4,5-\dfrac{1}{2}x-\dfrac{1}{3}-\dfrac{1}{6}\)
\(\Leftrightarrow4,5-\dfrac{1}{2}x=\dfrac{1}{6}+\dfrac{1}{3}=\dfrac{1}{2}\)
\(\Leftrightarrow\dfrac{1}{2}x=4,5-\dfrac{1}{2}=4\)
\(\Leftrightarrow x=4:\dfrac{1}{2}=8\)
    Vậy \(x=8\)

\(\#PeaGea\)