Question

tìm x

1-[ 4/9 +x -7/8] :3/4=0

ai làm nhanh mình tick và like cho

Answer 1

1 - [ 4/9 + x - 7/8 ]  : 3/4 =0

1-[ 4/9 + x - 7/8 ] = 0 x 3/4 = 0

4/9 + x - 7/8 = 1-0 = 1

4/9 + x = 1+7/8 = 15/8

x = 15/8 - 4/9 

x = 103/72 = 1 31/72

Vậy x = 1 131/72

mik ko chắc đúng đâu nha

Answer 2

1 - (4/9 + x - 7/8) : 3/4 = 0

1 - (4/9 + x - 7/8) = 0 x 3/4

1- (4/9 + x - 7/8) = 0

4/9 + x - 7/8 = 1 - 0

4/9 + x - 7/8 = 1

4/9 + x = 1 + 7/8

4/9 + x = 15/8

x = 15/8 - 4/9

x = 103/72

Answer 3

\(1-\left(\frac{4}{9}+x-\frac{7}{8}\right):\frac{3}{4}=0\)

\(\Rightarrow1-\left(\frac{4}{9}+x-\frac{7}{8}\right)=0\)

\(\Rightarrow\frac{4}{9}+x-\frac{7}{8}=1\)

\(\Rightarrow x-\frac{7}{8}=\frac{5}{9}\)

\(\Rightarrow x=\frac{103}{72}\)

Answer 4

ko phải các bạn ơi

Answer 5

\(\text{Tìm }x\text{ : }\)

\(1-\left[\frac{4}{9}+x-\frac{7}{8}\right]\text{ : }\frac{3}{4}=0\)

\(1-\left[\frac{4}{9}+x-\frac{7}{8}\right]=0\text{ x }\frac{3}{4}\)

\(1-\left[\frac{4}{9}+x-\frac{7}{8}\right]=0\)

\(\frac{4}{9}+x-\frac{7}{8}=1-0\)

\(\frac{4}{9}+x-\frac{7}{8}=1\)

\(\frac{4}{9}+x=1+\frac{7}{8}\)

\(\frac{4}{9}+x=\frac{15}{8}\)

\(x=\frac{15}{8}-\frac{4}{9}\)

\(x=\frac{103}{72}\)