\(1+2+3+...+x=300\)
\(\Rightarrow\frac{x.\left(x+1\right)}{2}=300\)
\(\Rightarrow x.\left(x+1\right)=600\)
\(\Rightarrow x.\left(x+1\right)=24.25\)
\(\Rightarrow x=24\)
PP/ss: Hoq chắc ạ_333
\(1+2+3+...+x=300\)
\(\frac{x\left(x+1\right)}{2}=300\)
\(x\left(x+1\right)=600\)
\(x\left(x+1\right)=24\cdot25\)
\(x=24\)
làm rồi mak bấm nút hủy tức chết mất!!
1 + 2 + 3 + .... + x = 300
=> x . ( x + 1 ) : 2 = 300
=> x . ( x + 1 ) = 300 . 2 = 600
=> x . ( x + 1 ) = 24 . 25
=> x = 24