Question

tìm X:

Answer 1

\(3^{x+1}-2=3^2+\left[5^2-3\left(2^2-1\right)\right]\)

\(\Rightarrow3^{x+1}-2=9+\left(25-9\right)\)

\(\Rightarrow3^{x+1}-2=25\)

\(\Rightarrow3^{x+1}=3^3\)

\(\Rightarrow x+1=3\Rightarrow x=2\)

Answer 2

\(\Rightarrow3^{x+1}=9+\left(25-3\cdot3\right)+2\\ \Rightarrow3^{x+1}=25-16\\ \Rightarrow3^{x+1}=9=3^2\Rightarrow x+1=2\Rightarrow x=1\)

Answer 3

b= 3^x+1 - 2 = 9 + [25 - 3.3]

3^x+1 - 2 = 9 + [25-9] = 9 + 16

3^x+1 - 2 = 25

3^x+1 = 25+2 = 27 = 3^3

x+1=3

x=2