Question

tìm x, y, z

15 x y - 2009 = 1201

[(z + 32 ) - 15 ] x 2 =60

[ 161 +  ( 153 - z) ] x 18 = 3870

[ 43 - ( 56 - z ) ] x 12 = 384

 

Answer 1

a) 15 x y - 2009 = 1201

 \(15.x.y=1201+2009\)

\(15.x.y=3210\)

\(x.y=3210:15\)

\(x.y=214\)

Tới đây bó tay

b)[(z + 32) - 15 ] . 2 = 60

\(\left(z+32\right)-15=60:2\)

\(\left(z+32\right)-15=30\)

\(\left(z+32\right)=30+15\)

\(z+32=45\)

\(z=45-32\)

\(z=13\)

c)[161 + (153-z)] .18 = 3870

\(161+\left(153-z\right)=3870:18\)

\(161+\left(153-z\right)=215\)

\(153-z=215-161\)

\(153-z=54\)

\(-z=54-153\)

\(-z=-99\)

\(z=99\)

d)[43 - (56 - z)] . 12 = 384

\(43-\left(56-z\right)=384:12\)

\(43-\left(56-z\right)=32\)

\(-\left(56-z\right)=32-43\)

\(56+z=-11\)

\(z=-11-56\)

\(z=-11-56\)

\(z=-67\)

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