Có:(x/2)^2=x^2/4
(y/3)^2=y^2/9
(z/4)^2=z^2/16
\(\Rightarrow\)\(\frac{x^2}{4}\)\(=\)\(\frac{y^2}{9}\)\(=\)\(\frac{z^2}{16}\)\(=\)\(\frac{x^2+y^2+z^2}{4+9+16}\)=\(\frac{29}{29}=1\)
\(\Rightarrow\)\(x^2=4\Rightarrow x=\pm2\)
\(y^2=9\Rightarrow y=\pm3\)
\(z^2=16\Rightarrow z=\pm4\)