Question

Tìm x, y 

\(\left(\frac{1}{2}x-5\right)^{20}+\left(y^2-\frac{1}{4}\right)^{10}\le0\)

Answer 1

Xét  \(\left(\frac{1}{2}x-5\right)^{20}\ge0\)

         \(\left(y^2-\frac{1}{4}\right)^{10}\ge0\)

\(\Rightarrow\)  \(\left(\frac{1}{2}x-5\right)^{20}+\left(y^2-\frac{1}{4}\right)^{10}\ge0\)

mà  \(\left(\frac{1}{2}x-5\right)^{20}+\left(y^2-\frac{1}{4}\right)^{10}=0\)

\(\Leftrightarrow\hept{\begin{cases}\frac{1}{2}x-5=0\\y^2-\frac{1}{4}=0\end{cases}}\)

\(\Rightarrow\hept{\begin{cases}\frac{1}{2}x=5\\y^2=\frac{1}{4}\end{cases}}\)

\(\Rightarrow\hept{\begin{cases}x=10\\y=\pm\frac{1}{2}\end{cases}}\)

Answer 2

x=10;y=1/2

Answer 3

x = 10

y = \(\frac{1}{2}\)

nha

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