\(\dfrac{x-7}{y-6}=\dfrac{7}{6}\)
⇔ \(\dfrac{x-7}{7}=\dfrac{y-6}{6}\)
⇔ \(\dfrac{x}{7}=\dfrac{y}{6}\)
Áp dụng tính chất dãy tỉ số bằng nhau, ta có:
\(\dfrac{x}{7}=\dfrac{y}{6}=\dfrac{x-y}{7-6}=-4\)
⇒ \(\left\{{}\begin{matrix}x=-28\\y=-24\end{matrix}\right.\)
Vậy ...
\(\dfrac{x-7}{y-6}=\dfrac{7}{6}\text{ và }x-y=-4\)
\(\text{Có }\dfrac{x-7}{y-6}=\dfrac{7}{6}\)
\(\Rightarrow6.\left(x-7\right)=7.\left(y-6\right)\)
\(\Rightarrow6.x-6.7=7.y-7.6\)
\(\Rightarrow6x=7y\)
\(\text{Mà }x-y=-4\)
\(\Rightarrow6x-6y=-24\)
\(\Rightarrow7y-6x=-24\)
\(\Rightarrow1y=-24\)
\(\text{Và }x-y=-4\)
\(\Rightarrow x=\left(-4\right)+y=\left(-4\right)+\left(-24\right)=-28\)
\(\text{Vậy }x=-28\)
\(y=-24\)
