\(xy+12=x+y\)
<=> \(xy-x-y+12=0\)
<=> \(x\left(y-1\right)-\left(y-1\right)+11=0\)
<=> \(\left(x-1\right)\left(y-1\right)=-11\)
làm nốt nha
\(x\left(y+1\right)=2y+5\)
<=> \(x\left(y+1\right)-2y-5=0\)
<=> \(x\left(y+1\right)-2\left(y+1\right)-3=0\)
<=> \(\left(x-2\right)\left(y+1\right)=3\)
làm nốt nha