24 tháng 12 2021 lúc 8:29
Các câu hỏi tương tự
15 tháng 1 2022 lúc 7:18
Bài 6. Tìm x, y biết
\(\text{(-9)x²+18x-17x²-2x+3 = y(y + 4)}\)
Thực hiện phép tính:a) dfrac{2}{5}xyleft(x^2y-5x+10yright)b) left(x^2-1right)left(x^2+2x+yright)c) left(x+3yright)^2d) left(4x-yright)^3e) left(x^2-2yright)left(x^2+2yright)g) 18x^4y^2z:10x^4yh) left(x^3y^3+dfrac{1}{2}x^2y^3-x^3y^2right):dfrac{1}{3}x^2y^2i) left(6x^3-7x^2-x+2right):left(2x+1right)k) dfrac{5x-1}{3x^2y}+dfrac{x+1}{3x^2y}l) dfrac{3x+1}{x^2-3x+1}+dfrac{x^2-6x}{x^2-3x+1}m) dfrac{2x+3}{10x-4}+dfrac{5-3x}{4-10x}n) dfrac{x}{x^2+2x+1}+dfrac{3}{5x^2-5}o) dfrac{x^2+2}{x^3-1}+dfrac{2}{x^2+x...
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Thực hiện phép tính:
a) \(\dfrac{2}{5}xy\left(x^2y-5x+10y\right)\)
b) \(\left(x^2-1\right)\left(x^2+2x+y\right)\)
c) \(\left(x+3y\right)^2\)
d) \(\left(4x-y\right)^3\)
e) \(\left(x^2-2y\right)\left(x^2+2y\right)\)
g) \(18x^4y^2z:10x^4y\)
h) \(\left(x^3y^3+\dfrac{1}{2}x^2y^3-x^3y^2\right):\dfrac{1}{3}x^2y^2\)
i) \(\left(6x^3-7x^2-x+2\right):\left(2x+1\right)\)
k) \(\dfrac{5x-1}{3x^2y}+\dfrac{x+1}{3x^2y}\)
l) \(\dfrac{3x+1}{x^2-3x+1}+\dfrac{x^2-6x}{x^2-3x+1}\)
m) \(\dfrac{2x+3}{10x-4}+\dfrac{5-3x}{4-10x}\)
n) \(\dfrac{x}{x^2+2x+1}+\dfrac{3}{5x^2-5}\)
o) \(\dfrac{x^2+2}{x^3-1}+\dfrac{2}{x^2+x+1}+\dfrac{1}{1-x}\)
p) \(\dfrac{4x+2}{15x^3y}\dfrac{5y-3}{9x^2y}+\dfrac{x+1}{5xy^3}\)
q) \(\dfrac{2x-7}{10x-4}-\dfrac{3x+5}{4-10x}\)
r) \(\dfrac{3}{2x+6}-\dfrac{x-6}{2x^2+6x}\)
x) \(\dfrac{4y^2}{11x^4}.\left(-\dfrac{3x^2}{8y}\right)\)
y) \(\dfrac{x^2-4}{3x+12}.\dfrac{x+4}{2x-4}\)
z) \(\left(x^2-25\right):\dfrac{2x+10}{3x-7}\)
t) \(\left(\dfrac{2x+1}{2x-1}-\dfrac{2x-1}{2x+1}\right):\dfrac{4x}{10x-5}\)
w) \(\left(\dfrac{1}{x^2+x}-\dfrac{2-x}{x+1}\right):\left(\dfrac{1}{x}+x-2\right)\)
Bài 1: Tính: a)dfrac{x+y}{2left(x-yright)}-dfrac{x-y}{2left(x+yright)}-dfrac{2y^2}{y^2-x^2} b)left(dfrac{9}{x^3-9x}+dfrac{1}{x+3}right):left(dfrac{x-3}{x^2+3}-dfrac{x}{3x+9}right)Bài 2: Tìm x: a)2x^3-50x0 b)x^3+x^2+x+a chia hết cho x+1Bài 3: Cho △MNP vuông tại N, biết MN 6cm, NP 8cm. đường cao NH, qua H kẻ HC⊥MN, HD⊥NP a) Chứng minh HDNC là hình chữ nhật. b) Tính CD c) Tính diện tích △NMH
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Bài 1: Tính:
a)\(\dfrac{x+y}{2\left(x-y\right)}-\dfrac{x-y}{2\left(x+y\right)}-\dfrac{2y^2}{y^2-x^2}\)
b)\(\left(\dfrac{9}{x^3-9x}+\dfrac{1}{x+3}\right):\left(\dfrac{x-3}{x^2+3}-\dfrac{x}{3x+9}\right)\)
Bài 2: Tìm x:
a)2x\(^3\)-50x=0 b)\(x^3+x^2+x+a\) chia hết cho x+1
Bài 3: Cho △MNP vuông tại N, biết MN = 6cm, NP = 8cm. đường cao NH, qua H kẻ HC⊥MN, HD⊥NP
a) Chứng minh HDNC là hình chữ nhật.
b) Tính CD
c) Tính diện tích △NMH
Bài 2:a. 2x^2+2xy+y^2+96x-left|y+3right| Leftrightarrowleft|y+3right|6x-2x^2-2xy-y^2-9 Leftrightarrowleft|y+3right|-x^2-2xy-y^2-x^2+6x-9 Leftrightarrowleft|y+3right|-left(x+yright)^2-left(x-3right)^2 Leftrightarrowleft|y+3right|-left[left(x+yright)^2+left(x-3right)^2right] Có: left|y+3right|ge0 -left[left(x+yright)^2+left(x-3right)^2right]le0 Do đó: left|y+3right|-left[left(x+yright)^2+left(x-3right)^2right]0 Leftrightarrowhept{begin{cases}y+30x+y0x-30end{cases}}Leftrightarrowhept{begin{cases}x3...
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Bài 2:
a. \(2x^2+2xy+y^2+9=6x-\left|y+3\right|\)
\(\Leftrightarrow\left|y+3\right|=6x-2x^2-2xy-y^2-9\)
\(\Leftrightarrow\left|y+3\right|=-x^2-2xy-y^2-x^2+6x-9\)
\(\Leftrightarrow\left|y+3\right|=-\left(x+y\right)^2-\left(x-3\right)^2\)
\(\Leftrightarrow\left|y+3\right|=-\left[\left(x+y\right)^2+\left(x-3\right)^2\right]\)
Có: \(\left|y+3\right|\ge0\)
\(-\left[\left(x+y\right)^2+\left(x-3\right)^2\right]\le0\)
Do đó: \(\left|y+3\right|=-\left[\left(x+y\right)^2+\left(x-3\right)^2\right]=0\)
\(\Leftrightarrow\hept{\begin{cases}y+3=0\\x+y=0\\x-3=0\end{cases}}\Leftrightarrow\hept{\begin{cases}x=3\\y=-3\end{cases}}\)
b. \(\left(2x^2+x-2013\right)^2+4\left(x^2-5x-2012\right)^2=4\left(2x^2+x-2013\right)\left(x^2-5x-2012\right)\)
\(\Leftrightarrow\left(2x^2+x-2013\right)^2-4\left(2x^2+x-2013\right)\left(x^2-5x-2012\right)+\left[2\left(x^2-5x-2012\right)\right]^2=0\)
\(\Leftrightarrow\left(2x^2+x-2013-2x^2+10x+4024\right)^2=0\)
\(\Leftrightarrow\left(11x+2011\right)^2=0\)
\(\Leftrightarrow11x+2011=0\)
\(\Leftrightarrow x=-\frac{2011}{11}\)
rut gon
a)\(\left(x-4\right)\left(x+4\right)x-\left(x^2+1\right)\left(x^2-1\right)\)
b)\(\left(y-3\right)\left(y+3\right)\left(y^2+9\right)-\left(y^2+2\right)\left(y^2-2\right)\)
c)\(x\left(x+\frac{1}{2}\right)-\left(2x-1\right)\left(x+\frac{3}{4}\right)\)
thực hiện phép chia:
a) \(\left(x-y\right)^5-\left(y-x\right)^3\)
b) \(\left(3y-6x\right)^3:9\left(2x-y\right)\)
c) \(\left[3\left(x-y\right)^5-2\left(x-y\right)^4+3\left(x-y\right)^2\right]:\left[5\left(x-y\right)^2\right]\)
Bài 1:Tìm x
a) \(x^3+9x^2+27x+19=0\)
b) \(x\left(x+5\right)\left(x-5\right)-\left(x+2\right)\left(x^2-2x+4\right)=3\)
c) \(\left(5-2x\right)^2-16=x\)
d) \(\left(x-3\right)^3-\left(x-3\right)\left(x^2+3x+9\right)+9\left(x+1\right)^2=15\)
Bài 2:Tìm x,y,z
\(x^2+2x+y^2-6y+4z^2-4z+11=0\)
Tính
\(\left(x-y\right)\left(x+y\right)\left(x^2+y^2\right)\left(x^4+y^4\right)\)
\(2x^2\left(x-2\right)+3x\left(x^2-x-2\right)-5\left(3-x^2\right)\)
\(\left(x-1\right)\left(x-3\right)-\left(4-x\right)\left(2x+1\right)-3x^2+2x-5\)
Tìm x:
a) 2x(x-5)-x(2x+3)=26
b) \(\left(3y^2-y+1\right)\left(y-1\right)+y^2\left(4-3y\right)=\frac{5}{2}\)
c) \(2x^2+3\left(x-1\right)\left(x+1\right)=5x\left(x+1\right)\)