Question

Tìm x, y biết:

\(\frac{x-y}{3}=\frac{x+y}{13}=\frac{xy}{200}\)

Answer 1

\(\frac{x-y}{3}=\frac{x+y}{13}=\frac{xy}{200}=\frac{x-y+x+y}{3+13}=\frac{2x}{16}=\frac{x}{8}\)

suy ra:\(\frac{xy}{200}=\frac{x}{8}\Rightarrow\frac{xy}{x}=\frac{200}{8}\Rightarrow y=25\)

\(\frac{x-y}{3}=\frac{x+y}{13}=\frac{xy}{200}=\frac{x-y-x-y}{3-13}=\frac{-2y}{-10}=\frac{y}{5}\)

suy ra:\(\frac{xy}{200}=\frac{y}{5}\Rightarrow\frac{xy}{y}=\frac{200}{5}\Rightarrow x=40\)

Answer 2

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