Question

Tìm x. y biết :

\(\frac{x-3}{y-2}=\frac{3}{2}\) và x - y = 4

Answer 1

Vì  x-3/y-2 = 3/2 

Nên 2(x-3) = 3(y-2)

Do đó : 2x - 6 = 3y - 6 nên 2x = 3y

=> 2x - 2y = y hay 2( x- y ) = y nên 2.4 = y

=> x = 3y/2 = 3.8/2 = 12 

Vậy x = 12 ; y = 8

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Answer 2

ta có :x-y=4 => x= 4 + y

\(\frac{x-3}{y-2}=\frac{3}{2}\)\(\Rightarrow2\cdot\left(x-3\right)=3\cdot\left(y-2\right)\)

                         \(\Rightarrow2x-6=3y-6\)

                          \(\Rightarrow2x-3y=6-6\)

                          \(\Rightarrow2x-3y=0\)

                          \(\Rightarrow2\cdot\left(4+y\right)-3y=0\)

                           \(\Rightarrow8+2y-3y=0\)

                           \(\Rightarrow8-y=0\Rightarrow y=8\)

 Thay y = 8 vào x = 4 + y \(\Rightarrow x=4+8\Rightarrow x=12\)

Answer 3

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