tim(x;y) biet -|2x+4| -|y+5| lon hon bang 0 .Tim cap (x;y)
tim x,y thuoc Z biet
|y|.|2x+3|=8
|2x+4|+|y-3|=0
|x-1|+|2y+7|=3
|x+5|+|2y+6| nho hon hoac bang 0
tim x,y,z thuoc Z biet /2x-4/+/y+2/+/2x+3y-z/=0
Tim cap x,y biet x,y thuoc Z va
2xy- 4+2x+y=0
tim cac so nguyen x,y biet
a)(x+5)2.(y-2)=8
b)(2x+4)10+(xy-y-6)=0
c)|x+y-5|+|x-y-3|=0
d)|(x-1)2-1|2015+4-(y-2)2017
Tim cac cap so nguyen x,y biet
a,xy=-5
b,(x+2)(2y-3)=8
c,(x-2)^2+(2x-y)^4=0
d,|x|+|y|=1
e,|2x+1|+|y|=4
f,|x-13|+|2y-8|<hoac= 0
g,|x-5|+|y+2|=2
h,|x+3|+|2y+1|=3
Tim so nguyen x,y biet
(x+1)^2+(y-1)^2=0
(x+3)×(y+1)=3
xy-2x=5
a, |x+2| + |y+3| =0
b, |x+y-2| + |y+5| = 0
c, |3x-15| + |2x+y+10| = 0
TIM X , Y BIET
A, I X- 3 I + I Y - 5 I < HOẶC = 0
B , I X- Y + 3 I + I Y - 4 I = 0