x+ ( x + 1) + (x+2) + ...+ (x+30) = 1240
x.31 + ( 1 + 2 + ...+ 30) = 1240
x.31 + [(1+30).30:2] = 1240
x.31 + 465 = 1240
x.31 = 775
x = 25
=31x+(1+2+3+..+30)=1240
=31x+465=1240
=31x=1240-465
31x=775
x=25
vậy x = 25
\(x+\left(x+1\right)+\left(x+2\right)+...+\left(x+30\right)=1240\)
\(\left(x+x+x+...+x\right)+\left(1+2+...+30=1240\right)\) ( 31 chư số x )
\(31x+\frac{30\cdot31}{2}=1240\)
\(31x+465=1240\)
\(31x=1240-465=775\)
\(x=\frac{775}{31}=25\)
Vậy ....
x+(x+1)+(x+2)+....+(x+30)=1240
31 . x + (1 + 2 + 3 + 4 +...+ 29 + 30) = 1240
31 . x + 31.15 = 1240
31 . x = 1240 - 31.15
31 . x = 775
x = 775 : 31
x = 25