\(x^2+5x+6=0\\ \Leftrightarrow x^2+2x+3x+6=0\\ \Leftrightarrow x.\left(x+2\right)+3.\left(x+2\right)=0\\ \Leftrightarrow\left(x+3\right)\left(x+2\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x+3=0\\x+2=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-3\\x=-2\end{matrix}\right.\)
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\(x^2+5x+6=0\)
\(x^2+5x+6=0\)
\(x^2+3x+2x+6=0\)
\(\left(x+2\right)\left(x+3\right)=0\)
\(x+2=0\)
\(x=-2\)
\(x+3=0\)
\(x=-3\)
Vậy: \(x=-2;x=-3\)
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