Question

Tìm x: x^2+12x-13=0 Giúp mình vs mình đang cần

Answer 1

 x^2+12x-13=0

= x² + 13x - x - 13 = 0

= x ( x + 13 ) - ( x + 13 ) = 0

= ( x - 1 ) ( x + 13 ) 

= 0 

= x = 1 

= x = -13

Hok tốt

Answer 2

x²+12x=13

xx+12x=13

x.(12+x)=13

x=0

hoặc x+12=0=> x= -12

Vậy, x = 0 hoặc x =-12

Answer 3

\(x^2+12x-13=0\)

\(\Leftrightarrow x^2+13x-x-13=0\)

\(\Leftrightarrow x\left(x+13\right)-\left(x+13\right)=0\)

\(\Leftrightarrow\left(x-1\right)\left(x+13\right)=0\Leftrightarrow x=1;x=-13\)