\(x^2-7x+10=0\)
\(\left(x^2-2x\right)-\left(5x-10\right)=0\)
\(x.\left(x-2\right)-5\left(x-2\right)=0\)
\(\left(x-2\right)\left(x-5\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-2=0\\x-5=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=2\\x=5\end{cases}}}\)
Vậy \(\orbr{\begin{cases}x=2\\x=5\end{cases}}\)
Tham khảo nhé~
\(x^2-7x+10=0\)
\(\Leftrightarrow x^2-5x-2x+10=0\)
\(\Leftrightarrow x\left(x-5\right)-2\left(x-5\right)=0\)
\(\Leftrightarrow\left(x-2\right)\left(x-5\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x-2=0\\x-5=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=2\\x=5\end{cases}}}\)
\(x^2-7x+10=0\)
\(\Rightarrow x^2-2x+5x+10=0\)
\(\Rightarrow x(x-2)-5(x-2)=0\)
\(\Rightarrow(x-5)(x-2)=0\)
\(\Rightarrow\hept{\begin{cases}x-5=0\\x-2=0\end{cases}\Rightarrow\hept{\begin{cases}x=5\\x=2\end{cases}}}\)\((\)tmđk\()\)
Chúc bạn học tốt :>
x-2 = 0
x = 2
hoặc x - 5 =0
x=5
học tốt
