Question

Tim x: x^2 - 2x + 1 = 25 ; 3(x-1)^2 - 3x(x-5)=1

Mn giup e vs <3

Answer 1

        \(x^2-2x+1=25\)

\(\Leftrightarrow\)\(\left(x+1\right)^2=25\)

\(\Leftrightarrow\)\(\orbr{\begin{cases}x+1=5\\x+1=-5\end{cases}}\)

\(\Leftrightarrow\)\(\orbr{\begin{cases}x=4\\x=-6\end{cases}}\)

Vậy...

       \(3\left(x-1\right)^2-3x\left(x-5\right)=1\)

\(\Leftrightarrow\)\(3\left(x^2-2x+1\right)-\left(3x^2-15x\right)=1\)

\(\Leftrightarrow\)\(3x^2-6x+3-3x^2+15x=1\)

\(\Leftrightarrow\)\(9x=-2\)

\(\Leftrightarrow\)\(x=-\frac{2}{9}\)

Vậy....

Answer 2

xin lỗi nhé, câu a mình làm sai:

a)  \(x^2-2x+1=25\)

\(\Leftrightarrow\)\(\left(x-1\right)^2=25\)

\(\Leftrightarrow\)\(\orbr{\begin{cases}x-1=5\\x-1=-5\end{cases}}\)

\(\Leftrightarrow\)\(\orbr{\begin{cases}x=6\\x=-4\end{cases}}\)

Vậy....