Question

Tìm x .

(x+1).(x+2).(x+5)-x^2.(x+8)= 27

Answer 1

(x+1).(x+2).(x+5)-x^2.(x+8)= 27

\(\Leftrightarrow\left(x^2+2x+x+2\right)\left(x+5\right)-x^3-8x^2-27=0\)

\(\Leftrightarrow x^3+5x^2+2x^2+10x+x^2+5x+2x+10-x^3-8x^2-27=0\)

\(\Leftrightarrow17x-17=0\)

\(\Leftrightarrow x=1\)

Answer 2

(x + 1).(x + 2).(x + 5) - x².(x + 8) = 27

<=> x³ + 8x² + 17x + 10 - x² - 8x² = 27

<=> 17x + 10 = 27

<=> 17x = 27 - 10

<=> 17x = 17

<=> x = 1

=> x = 1

Answer 3

Mình cần giải thích cặn kẽ ạ !