\(x\) \(\times\) \(\dfrac{1}{4}\) = 6 : 1 : 2
\(x\) \(\times\) \(\dfrac{1}{4}\) = 6:2
\(x\) \(\times\) \(\dfrac{1}{4}\) = 3
\(x\) = 3 : \(\dfrac{1}{4}\)
\(x\) = 12
Mình nhầm đoạn 6:1/2.nhờ bạn giải lại hộ mình với
\(x\)\(\times\) \(\dfrac{1}{4}\) = 6 : \(\dfrac{1}{2}\)
\(x\) \(\times\) \(\dfrac{1}{4}\) = 6 \(\times\) \(\dfrac{2}{1}\)
\(x\) \(\times\) \(\dfrac{1}{4}\) = 12
\(x\) = 12 : \(\dfrac{1}{4}\)
\(x\) = 48
Tính nhanh:
A = \(\dfrac{2}{3}\) + \(\dfrac{2}{9}\) + \(\dfrac{2}{27}\) + \(\dfrac{2}{81}\) + \(\dfrac{2}{243}\) + \(\dfrac{2}{729}\)
A \(\times\) 3 = 2 + \(\dfrac{2}{3}\) + \(\dfrac{2}{9}\) + \(\dfrac{2}{27}\) + \(\dfrac{2}{81}\) + \(\dfrac{2}{243}\)
A \(\times\) 3 - A = 2 - \(\dfrac{2}{729}\)
A \(\times\) ( 3 - 1) = 2 \(\times\) ( 1 - \(\dfrac{1}{729}\))
A \(\times\) 2 = 2 \(\times\) \(\dfrac{728}{729}\)
A = 2 \(\times\) \(\dfrac{728}{729}\) : 2
A = \(\dfrac{728}{729}\)
c, tính:
\(\dfrac{4}{5}\) + \(\dfrac{1}{2}\) - \(\dfrac{1}{6}\)
= \(\dfrac{4}{5}\) + \(\dfrac{1}{3}\)
= \(\dfrac{17}{15}\)
