Question

tìm x : (x+1/2)+(x+1/4)+(x+1/8)+(x+1/16)=1

 

Answer 1

x=\(\frac{1}{64}\)

Answer 2

(x+1/2)+(x+1/4)+(x+1/8)+(x+1/16) = (x+x+x+x)+(1/2+1/4+1/8+1/16) = 4x+(8/16+4/16+2/16+1/16) = 4x+15/16 = 1

=> 4x = 1 - 15/16 = 1/16 => x = 1/16 : 4 = 1/64 (= 0,015625)

Answer 3

(x+1/2)+(x+1/4)+(x+1/8)+(x+1/16) = (x+x+x+x)+(1/2+1/4+1/8+1/16) = 4x+(8/16+4/16+2/16+1/16) = 4x+15/16 = 1

=> 4x = 1 - 15/16 = 1/16 => x = 1/16 : 4 = 1/64 (= 0,015625)

\(\Rightarrow x=\frac{1}{64}\)

Answer 4

(x+1/2)+(x+1/4)+(x+1/8)+(x+1/16) = (x+x+x+x)+(1/2+1/4+1/8+1/16) = 4x+(8/16+4/16+2/16+1/16) = 4x+15/16 = 1

=> 4x = 1 - 15/16 = 1/16 => x = 1/16 : 4 = 1/64 (= 0,015625)

=>x=1/64

Vậy x=1/64