\(x-8=50\%\cdot x\)
\(x-8=0,5x\)
\(x-0,5x=8\)
\(x\left(1-0,5\right)=8\)
\(0,5x=8\)
\(\Rightarrow x=\frac{8}{0,5}=16\)
Vậy x cần tìm là 16
\(x-8=50\%x\)
\(x-8=\frac{1}{2}x\)
\(\Leftrightarrow\text{ }\frac{1}{2}x=x-8\)
\(x\cdot\frac{1}{2}=x-8\)
\(x\cdot\frac{1}{2}-x=-8\)
\(x\left(\frac{1}{2}-1\right)=-8\)
\(x\cdot\frac{-1}{2}=-8\)
\(x=-8\text{ : }\frac{-1}{2}\)
\(x=-8\cdot\frac{2}{-1}\)
\(x=16\)
\(x-8=50\%.x\)
\(\Leftrightarrow x-8=\frac{1}{2}x\)
\(\Leftrightarrow x-\frac{1}{2}x=8\)
\(\Leftrightarrow\frac{1}{2}x=8\)
\(\Leftrightarrow x=16\)
