\(x-2\sqrt{x}=0\Rightarrow\sqrt{x}\left(\sqrt{x}-2\right)=0\)
\(\Rightarrow\sqrt{x}=0\Rightarrow x=0\)
hoặc \(\sqrt{x}-2=0\Rightarrow\sqrt{x}=2\Rightarrow x=4\)
ban co the giai theo cach khac doc ko
\(x-2\sqrt{x}=0\Rightarrow\sqrt{x}\left(\sqrt{x}-2\right)=0\)
\(\Rightarrow\sqrt{x}=0\Rightarrow x=0\)
hoặc \(\sqrt{x}-2=0\Rightarrow\sqrt{x}=2\Rightarrow x=4\)
ban co the giai theo cach khac doc ko
Tim x, y, z biet
a ) |x-3,5|+ |x+5|=0
b) |x-1| + (y+1)^2 + |z-1|=0
c) ( x-1/3)^2 + (y-2)^2+ (z-1)^2 be hon hoac bang 0
d)(x-z)^2+ (y+x)^2 + (z+1/4)^2 =0
Cac ban giup minh voi minh can gap lam
tim x (x-3)(x+7)> hoac=0 nhanh len nha toi dang can gap
tim xeQ biet
a.-2x+1<7
b(x+2).(x-3)<0
minh can gap nha
nhanh mih se k
Tim x biet : can bac 2 cua 7 -x =x-1
Tim x:
(x-1)^x+2=(x-1)^x+6
mk dang can gap!!!
tim x biet : |x^2+x|+|(x+1)*(x-2)|=0
Tim x thuộc Z :
a) x^2-1/x^2 < 0
b) x^2 - 2/5 >= 0
c) x-2/x-6<0
f(x) = 2 (x^3 - x) + x^2 - 3x + 3 - x^3
a) Thu gon hai da thuc tren roi xep theo luy thua giam dan cua bien
b) Tinh f(-1);g (1/2)
c) Tim f(x) + g(x);f(x) - g(x)
d) Tim gia tri cua x de f(x) = g(x) (giup mk voi mk dang can gap)
tim x biet (2/5)^x>(2/5)^3.(-2/5)^2
CAN NGAY LAP TUC