\(\left(x-1\right)^2=\left|\frac{1}{4}-\frac{2}{4}-\frac{3}{4}\right|=\left|-1\right|=1\)
x-1=1 hoặc x-1=-1
x=2 hoặc x=0
=> (x-1)2 = /-1/
(x-1)2 = 1
(x-1)2= 12
=> x-1 = 1
x = 1 +1
x = 2
Vậy x = 2
Tìm x
\(\frac{5}{2}-\left(\frac{3}{2}-2\frac{1}{3}+x\right)=\frac{8}{15}-\left(\frac{1}{4}-\frac{7}{10}\right)\)
\(1\frac{2}{3}-1\frac{3}{5}+x=\frac{2}{5}-\left|\frac{3}{4}-\frac{7}{8}\right|\)
\(2-\left(\frac{2}{3}-3\frac{1}{4}+x\right)=1\left|\frac{1}{6}-\frac{13}{12}\right|\)
1, Tính \(\frac{1}{2}-\left(\frac{1}{3}+\frac{2}{3}\right)+\left(\frac{1}{4}+\frac{2}{4}+\frac{3}{4}\right)-\left(\frac{1}{5}+\frac{2}{5}+\frac{3}{5}+\frac{4}{5}\right)+...+\left(\frac{1}{100}+\frac{2}{100}+\frac{3}{100}+...+\frac{99}{100}\right)\)2,Tính \(\left(1-\frac{1}{2^2}\right)x\left(1-\frac{1}{3^2}\right)x\left(1-\frac{1}{4^2}\right)x...x\left(1-\frac{1}{n^2}\right)\)
Tìm x :
a) \(\left(\frac{3}{4}x+3\right)-\left(\frac{2}{3}x-4\right)-\left(\frac{1}{6}x+1\right)=\left(\frac{1}{3}x+4\right)-\left(\frac{1}{3}x-3\right)\)
b) \(\frac{x+1}{3}=\frac{x-2}{4}\)
Tìm x thuộc Z, biết:
\(\frac{4}{3}.\left(\frac{1}{6}-\frac{1}{2}\right)
1. tìm x biết:
a, \(\left(\frac{2}{3}+x\right)\frac{1}{2}-\frac{1}{3}x=\frac{5}{4}\)
b,\(\left|x+\frac{1}{2}\right|+\frac{1}{2}=\left|\frac{2}{3}-\frac{5}{4}\right|\)
c,\(\left(x+\frac{2}{3}\right)^2.\frac{1}{2}=1\frac{1}{2}\)
Tìm x biết:
a) \(-4\frac{3}{5}.2\frac{4}{23}
\(\text{Tìm }x,\text{ }\text{biết:}\)
\(1\text{)}\text{ }2.\left(x-\frac{1}{3}\right)-3\left(x-\frac{1}{2}\right)=\frac{1}{2}x\)
\(2\text{) }-3\left(x-\frac{1}{4}\right)-\frac{1}{3}\left(x+\frac{1}{2}\right)=x\)
\(\text{3) }\frac{3}{2}\left(x-\frac{5}{3}\right)-\frac{4}{5}=x+1\)
\(\text{4) }\frac{1}{6}\left(2.x-3\right)=\frac{1}{2}\left(-x+\frac{1}{4}-\frac{2}{3}\right)\)
\(\text{5) }-\frac{2}{3}\left(x-\frac{1}{4}\right)=\frac{1}{3}\left(2.x-1\right)\)
Tìm x
a)\(\frac{1}{5}-\frac{2}{3}+2x=\frac{1}{2}\)
b)\(4\left(\frac{1}{3}-3\right)+\frac{1}{2}=\frac{5}{6}+x\)
c)\(3\left(\frac{1}{2}-x\right)-5\left(x-\frac{1}{10}\right)=-\frac{7}{4}\)
d)\(4\left(\frac{3}{4}+x\right)-\frac{1}{5}=7x-\frac{1}{7}\)
Tìm x biết :
a)\(\frac{2}{3}x-50\%x-\left(-\frac{4}{5}\right):1\frac{3}{5}=-0,12\)\(+1\frac{3}{25}\)
b)\(\left(-1\frac{1}{6}+\frac{2}{3}-\frac{3}{4}\right):x+\left(-1\frac{11}{12}\right).1\frac{21}{23}=-6\frac{1}{3}\)
c)\(50\%x-\frac{1}{3}x-\left(\frac{-2}{3}\right)^2.\left(-1\frac{1}{8}\right)=-119\frac{3}{4}+120\frac{5}{6}\)
Tìm x :
a) \(\frac{3}{2}x-\frac{2}{3}=\frac{2}{3}:\frac{3}{2}\)
b) \(\left(\frac{9}{11}-x\right):\left(\frac{-10}{11}\right)=1-\frac{4}{5}\)
c) \(\frac{-11}{12}.x+\frac{3}{4}=\frac{-1}{6}\)
d) \(\frac{-5}{4}-\left(1\frac{1}{2}+x\right)=4,5\)
đ) \(\left(\frac{3}{4}-x:\frac{2}{15}\right).\frac{1}{5}=-2,6\)
e) \(3-\left(\frac{1}{6}-x\right).\frac{2}{3}=\frac{2}{3}\)
f) \(\left(1-2x\right).\frac{4}{5}=\left(-2\right)^3\)
g) \(\frac{1}{6}-\left|\frac{1}{2}.x-\frac{1}{3}\right|=\frac{1}{8}\)
