Question

Tìm x:   (x-1) ^x+2 = (x-1) ^x+4

Có ai giúp mk ko ?????

Answer 1

mk ko bt ??????????????

Answer 2

( x - 1 )^x . ( x - 1 ) ² = (x - 1 ) ⁴ . (x - 1 )^x

\(\frac{\left(x-1\right)^4}{\left(x-1\right)^2}=\frac{\left(x-1\right)^x}{\left(x-1\right)^x}\)

\(\left(x-1\right)^2=1\)

\(x-1=1\)

\(x=2\)

Answer 3

\(\left(x-1\right)^{x+2}=\left(x-1\right)^{x+4}\)

\(\Rightarrow\left(x-1\right)^x.\left(x-1\right)^2=\left(x-1\right)^x.\left(x-1\right)^4\)

\(\Rightarrow1=\left(x-1\right)^2\)( chia cả 2 vế cho \(\left(x-1\right)^x.\left(x-1\right)^2\))

\(\Rightarrow\orbr{\begin{cases}x-1=1\\x-1=-1\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}x=2\\x=0\end{cases}}\)

Vậy..........