Tách riêng thánh hai nhóm (x+x+x+...+x)+(1+4+7+10+...+28)=10x+145=156. Vậy x=11/10
\(\left(x+1\right)+\left(x+4\right)+...........+\left(x+28\right)=156\)
\(\Rightarrow x+1+x+4+..........+x+28=156\)
\(\Rightarrow10x+\left(1+4+.........+28\right)=156\)
\(\Rightarrow10x+145=156\)
\(\Rightarrow10x=11\)
\(\Rightarrow x=1,1\)