\(\left(x-3\right).\left(x+y\right)=-7\)
\(\Rightarrow x-3=-7\Rightarrow x=-4\)
\(\Rightarrow\left(-4-3\right).\left(-4+y\right)=-7\)
\(=-7.\left(-4+y\right)=-7\)
\(\left(-4\right)+y=\left(-7\right):\left(-7\right)\)
\(\left(-4\right)+y=1\Rightarrow y=5\)
Vậy : \(x=-4\) ; \(y=5\)