\(|x|-2=14\)
\(|x|=14+2\)
\(|x|=16\)
\(\Rightarrow x=\pm16\)
Vậy \(x\in\left\{\pm16\right\}\)
\(\left|x\right|-2=14\)
\(\Leftrightarrow\left|x\right|=14+2\)
\(\Leftrightarrow\left|x\right|=16\)
\(\Leftrightarrow\orbr{\begin{cases}x=16\\x=-16\end{cases}}\)
Vậy \(x=16\)hoặc \(x=-16\)