Cho | x | lon hon hoac bang 3 ; | y | = 5 , x; y thuoc tap hop Z . tim x ; y
Tap hop A x thuoc N 2 lon hon hoac bang va be hon hoac bang 78.
hay viet cac tap hop sau bang cach khac
A={ 9;11;13;...;99]
B={ 12 ; 24 ; 36 ;48}
M= { THANG 4 ; THANG 6 ;THANG 9 ; THANG 11}
N = { X THUOC N / X LON HON HOAC BANG 3 , LON HON HOAC BANG 10}
Q = { X THUOC N / X LON HON 0 ,BE HON 10}
Tim x biet:
A. (x-3/4).(3x+1/2)lon hon hoac bang 0
B. (2x+1).(4x+3)be hon hoac bang 0
tim cac so tu nhien x sao cho:
A. x thuoc B (12) va 20 được hon hoac nổ x là hon hoac nổ 50
B.x chia het cho 15 va 0<x be hon hoac bang 40
Cx thuoc U (20) va x> 8
D. 16 chia het cho x
Tïm n thuoc N sao cho
a) 24 : het 2n - 1(n lon hon hoac bang 1)
b) 4n - 7 : het 2n - 1 (n lon hon hoac bang 1)
tim x
3 | x - 2 | + 2x = 19 , x lon hon hoac bang 2
A={x thuoc N /7nho hon hoac bang x nho hon hoac bang 50, x chia het cho 7
a, viet tap hop A bang cach liet ke cac phan tu
b, tim sophan tu cua tap hop tren
(1+1/2)×(1+1/3)×(1+1/4)×....×(1+1/n)
Tim n biet n thuoc N va n lon hon hoac bang 2