l - x - 3 l + ( - l 49 l ) = 27
l - x - 3 l + ( - 49 ) = 27
l - x - 3 l = 27 - ( - 49 )
l - x - 3 l = 76
=> \(\orbr{\begin{cases}-x-3=76\\-x-3=-76\end{cases}}\)=> \(\orbr{\begin{cases}-x=76+3\\-x=-76+3\end{cases}}\)=> \(\orbr{\begin{cases}-x=79\\-x=-73\end{cases}}\)=> \(\orbr{\begin{cases}x=-79\\x=73\end{cases}}\)
Vậy x thuộc { - 79 ; 73 }
| -x - 3| + |49| = 27
=> -x - 3 + 49 = 27 hoặc -x - 3 + 49 = -27
-x - 3 = 27 - 49 -x - 3 = (-27) - 49
-x - 3 = -22 -x - 3 = -76
-x = (-22) + (-3) -x = (-76) + (-3)
-x = -25 -x -79
Vậy -x = -25; -x = -79
| -x - 3| + |49| = 27
=> -x - 3 + 49 = 27 hoặc -x - 3 + 49 = -27
-x - 3 = 27 - 49 -x - 3 = (-27) - 49
-x - 3 = -22 -x - 3 = -76
-x = (-22) + (-3) -x = (-76) + (-3)
-x = -25 -x -79
Đáp số:....................
P/s tham khảo nha
\(|-x-3|-|49|=27\)
\(|-x-3|-49=27\)
\(|-x-3|=76\)
\(Th1:-x-3=76\Leftrightarrow-x=79\Leftrightarrow x=-79\)
\(Th2:-x-3=-76\Leftrightarrow-x=-73\Leftrightarrow x=73\)
\(|5-x|+x=5\)
\(|5-x|=5-x\)
\(Th1:5-x=5-x\Leftrightarrow-x+x=-5+5\Leftrightarrow x=0\)
\(Th2:5-x=-5+x\Leftrightarrow-x-x=-5-5\Leftrightarrow-2x=-10x=5\)
\(|x-9|-9=-x\)
\(|x-9|=-x+9\)
\(Th1:x-9=-x+9\Leftrightarrow x+x=9+9\Leftrightarrow2x=18\Leftrightarrow x=9\)
\(Th2:x-9=x-9\Leftrightarrow x-x=-9+9\Leftrightarrow x=0\)
a,\(\left|-x-3\right|+\left(-\left|49\right|\right)=27\)
\(=>\left|-x-3\right|-49=2\)
\(=>\left|-x-3\right|=2+49=51\)
\(=>\orbr{\begin{cases}-x-3=51\\-x-3=-51\end{cases}}\)
\(=>\orbr{\begin{cases}-x=54\\-x=-48\end{cases}=>\orbr{\begin{cases}x=-54\\x=48\end{cases}}}\)
\(b,\left|5-x\right|+x=5\)
\(=>\left|5-x\right|=5-x\)
\(=>\orbr{\begin{cases}5-x=5-x\\5-x=-5+x\end{cases}}\)
\(=>\orbr{\begin{cases}x=x\\5+5=x+x\end{cases}=>\orbr{\begin{cases}x=x\\x=5\end{cases}}}\)
\(\)
\(c,\left|x-9\right|-9=-x\)
\(=>\left|x-9\right|=-x+9\)
\(=>\orbr{\begin{cases}x-9=-x+9\\x-9=x-9\end{cases}}\)
\(=>\orbr{\begin{cases}x+x=9+9\\x=x\end{cases}}=>\orbr{\begin{cases}x=9\\x=x\end{cases}}\)
d,\(d,\left|x-4\right|=x-6\)
\(=>\orbr{\begin{cases}x-4=x-6\\x-4=-x+6\end{cases}}\)
\(=>\orbr{\begin{cases}x-x=-6+4=-2\\x+x=6+4=10\end{cases}}\)
\(=>\orbr{\begin{cases}0=2\\x=\frac{10}{2}\end{cases}}\)
