Theo đề bài, ta có: \(3x-4⋮x-1\)
\(\Rightarrow3\left(x-1\right)-1⋮x-1\)
\(\Rightarrow-1⋮x-1\)
Vì \(x\in Z\Rightarrow x-1\inƯ\left(-1\right)=\left\{\mp1\right\}\)
Ta có các trường hợp sau:
\(\orbr{\begin{cases}x-1=1\\x-1=-1\end{cases}}\Rightarrow\orbr{\begin{cases}x=2\\x=0\end{cases}}\)
Vậy \(x\in\left\{2;0\right\}\)
3x - 4 \(⋮\) x - 1
\(\Rightarrow3\left(x-1\right)-1⋮x-1\)
\(\Rightarrow1⋮x-1\)
\(\Rightarrow x-1\inƯ\left(1\right)=\left\{-1;1\right\}\)
\(\Rightarrow x\in\left\{0;2\right\}\)
Vậy \(x\in\left\{0;2\right\}\)
@@ Học tốt
