Question

Tìm x  thuộc Z biết:

(x+1)+(x+3)+(x+5)+....................+(x+99)=0

Answer 1

 

(x+1)+(x+3)+(x+5)+....................+(x+99)=0

=>x+1+x+3+x+5+...+x+99=0

=>(x+x+x+....+x)+(1+3+5+...+99)=0

=>50x+(1+99).50/2=0

=>50x+2500=0

=>50x=-2500

=>x=-50

Answer 2

x + 1 +x + 3 + ......  + x + 99 = 0

50x = -2500

x = -50