\(\Leftrightarrow\hept{\begin{cases}x^2=25\\-5=x\end{cases}}\)
\(\Rightarrow x=\sqrt{25}=-5\)ko thể =5 vì -5=x
tìm x thuộc z , biết:
\(\frac{45}{x+1}\)= \(\frac{10.\left(x+1\right)}{2}\)
\(\frac{x^2}{-5}\)\(=\) \(\frac{25}{x}\)
\(x^2\)\(\times\)\(x\)\(=\) \(25\)\(\times\)\(\left(-5\right)\)
\(x\) \(\times\)\(x\)\(\times\)\(x\)\(=\) \(-125\)
\(x^3\)\(=\)\(-125\)
\(x^3\)\(=\)\(-5^3\)
\(\Rightarrow\)\(x\)\(=\)\(-5\)