(x - 3).(x + 2) < 0
=> x - 3 và x + 2 trái dấu
Mà x + 2 > x - 3
=> x + 2 > 0 => x > -2
x - 3 < 0 => x < 3
=> -2 < x < 3, mà x thuộc Z => x \(\in\) {-1;0;1;2}
tim x thuoc Z biet :
(x-1)^2 =(x-3)^4
HELP ME:0!!
Tim x biet
(x-2)(x+3)<0 voi x thuoc z
tim x thuoc Z biet (x-7)x(x+3)<0
Tim x, y thuoc Z biet : | x-2| + (x-y+1)^2 =0
tim x thuoc z,biet
(x-5)^2=0
tim x thuoc z biet
(x-1)(x-3)=-5
(x+1)(x+4)=0
(x^2-4)(x^2-19)<0
tim x,y thuoc z biet (x-2).(y+12)<0
tim x thuoc z biet
x^2(x-2)>0
tim x,y,z thuoc z biet /x/+/y/+/z/=0
