Lời giải:
Nếu $x\geq 2$ thì:
$x-2-5(x-4)=20-5x$
$x-2=20-5x+5(x-4)=0$
$\Rightarrow x=2$ (tm)
Nếu $x<2$ thì:
$2-x-5(x-4)=20-5x$
$2-x=20-5x+5(x-4)=0$
$\Rightarrow x=2$ (loại do $x<2$)
Vậy $x=2$
tim x thuoc z , biet : 2x-3/3 + -3x +4/4+5x-12/5 = 241/60
tim x thuoc z biet x+5:x-2
Tim x,y thuoc Z biet
a, xy - 2x - 3y = 5
b,5xy - 5x + y = 5
c,x + xy + y = 9
tim x thuoc z biet
(x-1)(x-3)=-5
(x+1)(x+4)=0
(x^2-4)(x^2-19)<0
tim x thuoc Z biet :
(x-1)^2 =(x-3)^4
HELP ME:0!!
tim x thuoc z,biet
(x-5)^2=0
cho a thuoc z biet :
a cong x bang 5
a - x bang 2
tim a,b thuoc z biet :
a công x bằng b
a trừ x bằng b
tim x,y thuoc z biet
-24/-6 = x/3 = 4/y^2 = z^3/-2
Tim x thuoc Z biet :
a . | 2x - 5 | = 13
b. | 7x + 3 | = 66
c. | 5x - 2 | < hoac bang 13
Giup to voi
