a) | x -2 | + 2 - x =0
=> x- 2 +2-x =0
=> 0x = 0
=> x E Z
b) |x-2|-3=-x
=> |x-2| = -x +3
xét 2th
th1: x-2 = -x+3
=> 2x = 5
=> x=2,5
th2 x-2 = x-3
=> 0= -1( vô lý)
vậy..
a) =>/x-2/=x-2
=>x-2>=0
=>x>=2
Vậy x>=2
b)=>/x-3/=-x+3
=>/x-3/=-(x-3)
=>x-3=<0
=>x=<3
Vậy x=<3