\(a,3-x=8-2x\)
\(\Leftrightarrow x=5\)
Vậy...
\(b,\left|4x+3\right|+5x=5+5x\)
\(\Leftrightarrow\left|4x+3\right|=5\)
\(\Leftrightarrow\orbr{\begin{cases}4x+3=5\\4x+3=-5\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=0.5\\x=-2\end{cases}}\)
vậy ...
a, 3-x = 8-2x
3-8 = -2x+x
-5 = -x
5 = x
Vậy x=5
b, | 4x+3 | + 5x = 5 + 5x
| 4x+3 | = 5
\(\Rightarrow\orbr{\begin{cases}4x+3=5\\4x+3=-5\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{1}{2}\\x=-2\end{cases}}\)
Vậy............................................
\(a,3-x=8-2x\)
\(-x+2x=8-3\)
\(x=5\)
\(b,|4x+3|+5x=5+5x\)
\(|4x+3|=5+5x-5x\)
\(|4x+3|=5\)
\(Th1:4x+3=5\Leftrightarrow4x=2\Leftrightarrow x=\frac{1}{2}\)
\(Th2:4x+3=-5\Leftrightarrow4x=-8\Leftrightarrow x=-2\)
